Question

find the sum of first n odd natural number

Answer 1

odd=1
even=2
sum=2+1
=3

hope it helps u.....

Answer 2

1,3,5,7,..............n terms are n odd numbers which are in A.P.

a=1
d=2

sum of n terms of an ap = n/2(2a+(n-1)d)
= n/2(2×1+(n-1)×2)
= n/2(2+2n-2)
= n/2×2n
=n^2
therefore, the sum of n odd numbers is n^2