Question

Find the sum of first n odd natural numbers.​

Answer 1

Answer:

Hence this series is an Arithmetic Progression. First term of this sequence is 1 and the common difference is 2. So we get our sequence is arithmetic progression with a = 1 and d = 2. Hence the sum of the first n odd natural number is n2.

plz follow me

Answer 2

$\large\underline{ \underline{ \sf \maltese{ \: Question⤵ }}}$

Find the sum of first n odd natural numbers.

❇ Solution ⬇

The sequence of first n odd numbers is

1,3,5,7.........n

This forms an A.P with a=1 and d=2

S = n/2{2a+(n−1)d}

⇒S = n/2{2(1)+(n−1)2}

⇒S = n/2(2n)

⇒S = n²

Thank you.