Find the sum of first 'n' odd positive integers
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7
first odd positive no. (2k+1)
Anonymous:
how are you
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13
first odd no. =1 =a
difference between two odd numbers=2 =d
no of odd numbers=n
Sn=(n/2){2a +(n-1)d}
=(n/2){2+(n-1)2}
=n(1+n-1)
difference between two odd numbers=2 =d
no of odd numbers=n
Sn=(n/2){2a +(n-1)d}
=(n/2){2+(n-1)2}
=n(1+n-1)
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