find the sum of first n terms of the AP 6,4,2.......
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Answer:
here
a= 6
d = 4-6 = -2
Sn = n/2(2a+(n-1)*d)
= n/2(2*6+(n-1)*(-2))
= n/2(12-2n+2)
n/2(14-2n)
= n(7-n)
sun of first n terms = n(7-n)
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