find the sum of first n terms root 2 + root 8 + root 18 + root 32
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here the series formed is √2+2√2+3√2..........................
sn=n/2(2a+(n-1)d)
sn=n/2(2√2+(n-1)√2)
=n/2(√2+√2n)
=n/√2+n²/√2
sn=n/2(2a+(n-1)d)
sn=n/2(2√2+(n-1)√2)
=n/2(√2+√2n)
=n/√2+n²/√2
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hope it will help uh ..
nd plz mark as brainliest ..☺☺
nd plz mark as brainliest ..☺☺
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