find the sum of first natural numbers from 11 to 20
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Answered by
6
Given,
a = 11
d = 1
We know that,
![S_{10} = \frac{n}{2} [2a + (n - 1)d] \\ \\ S_{10} = \frac{10}{2} [2(11) + (10 - 1)1] \\ \\ S_{10} = 5(22 + 9) \\ \\ S_{10} = 5(31) \\ \\ S_{10} = 155](https://tex.z-dn.net/?f=S_%7B10%7D+%3D+%5Cfrac%7Bn%7D%7B2%7D+%5B2a+%2B+%28n+-+1%29d%5D+%5C%5C+%5C%5C+S_%7B10%7D+%3D+%5Cfrac%7B10%7D%7B2%7D+%5B2%2811%29+%2B+%2810+-+1%291%5D+%5C%5C+%5C%5C+S_%7B10%7D+%3D+5%2822+%2B+9%29+%5C%5C+%5C%5C+S_%7B10%7D+%3D+5%2831%29+%5C%5C+%5C%5C+S_%7B10%7D+%3D+155 "S_{10} = \frac{n}{2} [2a + (n - 1)d] \\ \\ S_{10} = \frac{10}{2} [2(11) + (10 - 1)1] \\ \\ S_{10} = 5(22 + 9) \\ \\ S_{10} = 5(31) \\ \\ S_{10} = 155")
If any doubt, please ask ;)
a = 11
d = 1
We know that,
If any doubt, please ask ;)
Anonymous:
Kaatil answer !
Thanka :see_no_evil:
Answered by
0
Answer:
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