find the sum of first nth term of AP is 6,2,-2 fill ups
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given the sequence which is defined by.
a
n
=6n+2.....eq(1)
and we know that nth term of an A.p is given by
a
n
=a
1
+(n−1)d
which can also be written as
a
n
=a
1
−d+nd.....eq(2)
comparing eq(1) and eq(2) we get
common difference is
d=6 (by comparing coefficients of n)
and
a
1
−d=2
by putting value of d=b in above equation we get
a
1
−6=2
⟹a
1
=8 (first term of A.P)
hence if a and b are real numbers this sequence form an A.P with first term a
1
=8
and have a common difference d=6
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