find the sum of first nth terms of the list of numbers whose magnitude nth term is given by
An = 3+2n
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Good evening ✴️✴️✴️✴️
Your answer is given in the attachment in detail
I hope it will help you
Thanks
♠️♠️♠️♠️♠️♠️♠️♠️♠️♠️♠️
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copied because it is showing of 24 terms!
Answered by
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Put n =1
An = 5
Put n=2
An = 7
Put n=3
An = 9
Series - 5,7,9,11......
It is an AP with d = 2
Sum of n terms = n/2 [2a+(n-1)d]
n/2 [10+(n-1)2]
n/2 [8+2n]
.
.
.
Which is the required answer!
An = 5
Put n=2
An = 7
Put n=3
An = 9
Series - 5,7,9,11......
It is an AP with d = 2
Sum of n terms = n/2 [2a+(n-1)d]
n/2 [10+(n-1)2]
n/2 [8+2n]
.
.
.
Which is the required answer!
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