find the sum of first seven numbers which are multiples of t2 as well as of 9?
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72
so the 7 no.s divisible by 2 as well as 9 =18,36,54,72,90,108,126....so as u can see they are the multiples of 18=2*9...so the common difference of the a.p. is 18...so the sum of the no.s => 7/2 {2*18+(7-1)18} = 7/2(36+108)=7/2*144=504
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17
nos. that are multiples of 2 and 9 are 18, 36, 54, 72, 90, 108, 126 and so on.
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