find the sum of first ten even positive integers
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the sum of first ten even positive integers is 2+4+6+8+10+12+14+16+18+20=110
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first ten even positive numbers = 2,4,6......20
they are in AP
a=2 l=20
d=2
n=10sum of first ten even positive integers=n/2(a+l)
=10/2(2+20)
=5(22)
= 110
they are in AP
a=2 l=20
d=2
n=10sum of first ten even positive integers=n/2(a+l)
=10/2(2+20)
=5(22)
= 110
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