Question

Find the sum of first ten multiples of 4
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Answer 1

Answer:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40

So,

a = 4

l (last term) = 40

d = 4

n = 10

So,

S10 = n/2*(a + l )

= 10/2*(4+40)

=5*44

=220

Answer 2

Answer:

Answer:226

Step by step answer:

4+8+12+16+20+24+28+32+36+40=226