Question

Find the sum of first ten terms of the arithmetic sequence 5,8,11

Answer 1

Answer:

The sum of first ten terms of the given AP is 185

Step-by-step explanation:

We have the formula for finding the sum of n terms of an AP,

$S_{n} = \frac{n}{2} [2a+(n-1)d]$

here,

The first term $a=5$

common difference $d=8-5=3$

and given $n=10$

Applying in the formula we get $S_{10}= \frac{10}{2} [2(5)+(10-1)(3)]$

                                                          $=5[10+27]=185$.

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