Find the sum of first twelve multiples of 7.
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9
546 is the sum of the first twelve of 7
Answered by
24
First 12 multiples of 7 are= 7,14,21.......
a=7
d=7
n=12
s12= n/2{2a +(n-1)d}
s12= 12/2{2x7+(12-1)7}
= 6(14+77)
= 6(91)
=546
The answer is 546.
a=7
d=7
n=12
s12= n/2{2a +(n-1)d}
s12= 12/2{2x7+(12-1)7}
= 6(14+77)
= 6(91)
=546
The answer is 546.
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