Math, asked by mehak380, 8 months ago

Find the sum of first twelve odd natural numbers.

Answers

Answered by priyomrabhadas
11

Answer:

apply the input parameter values in the AP formula

Sum = n/2 x (a + Tn)

= 12/2 x (1 + 23)

= (12 x 24)/ 2

= 288/2

1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21+ 23 = 144

Therefore, 144 is the sum of first 12 odd numbers.

Step-by-step explanation:

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Answered by AnkitaSahni
0

144 is the sum of the first 12 odd natural numbers.

Given:

First twelve odd natural numbers.

To Find:

We have to find the sum of the first twelve odd natural numbers.

Solution:

This is a simple problem from AP.

Let us tackle this problem.

We can easily solve this problem as follows,

We apply the input parameter values in the AP formula,

Sum = \frac{n}{2} * (a+T_{n} )

Where,

n = total number of terms

a = 1st term

Tn = Last term

So,

Sum =  \frac{12}{2} * (1+23)

= 6*24

=144

Hence,

1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21+ 23 = 144

Therefore, 144 is the sum of first 12 odd natural numbers.

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