Question

find the sum of first twenty-five natural numbers which are divisible by 6​

Answer 1

Answer:

210

Step-by-step explanation:

a = 6   d=6   n=25

$Sn = \frac{n}{2} [2a + (n-1)*d]$

S10 = 10/2 (2*6 + 5*6)

      = 5 (12+30)

      =5(42)

      = 210

HOPE YOU NDERSTOOD THE SOLUTION

Answer 2

Sn= n/ 2 ( t1 +tn )

Sn= n/ 2 ( 6 + 24 )

Sn = 4/2 ( 30 )

Sn= 2 × 30

Sn = 60

[ there fore the sum of first 25 natural numbers divisible by 6 is 60 ]