Question

find the sum of first twenty four terms of arthemetic series 5+8+11+14.........using suitable formula​

Answer 1

Here is your answer mate

Hope it helped you

Answer 2

Answer:

940

Step-by-step explanation:

a=5

d= 8-5 = 3

n = 24

So the sum of n terms of an AP is = n/2 (2a+(n-1)d)

Substituting all

24/2*(2*5+(24-1)*3)

12*(10+69)

12*79

= 940

Hope it helps you