Question

find the sum of first twentyfour times of AP and its nth term is 4n-3​

Answer 1

Step-by-step explanation:

t

n

=4n−3

Put n = 1

∴t

1

=4×1−3

=4−3=1

∴ First term (t

1

)=1

Put n = 2

∴t

2

=4×2−3

=8−3=5

∴ Second term (t

2

)=5

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