find the sum of five terms of the squence √3,√12,√27
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Answered by
0
the answer to your question is √3+√12+√27
=>√3+2√3+3√3
=>6√3
=>√3+2√3+3√3
=>6√3
Answered by
1
here,a=√3
d=a2 -a1
=√12 -√3
=2√2-√3
d=√3
n=5
with the formula,
sn = n/2[2a + (n-1)d]
sn = 5/2 [2√3 + (5-1)√3)]
sn =5/2[6√3]
sn=15√2
thus sum of five terms in this AP ,
=15√3
hope it helps!!!!
d=a2 -a1
=√12 -√3
=2√2-√3
d=√3
n=5
with the formula,
sn = n/2[2a + (n-1)d]
sn = 5/2 [2√3 + (5-1)√3)]
sn =5/2[6√3]
sn=15√2
thus sum of five terms in this AP ,
=15√3
hope it helps!!!!
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