Question

find the sum of following 4 1/3 +
5 2/5​

Answer 1

Answer:

146/15 or 9 11/15

Step-by-step explanation:

question is asking to sum both the rational numbers 4 1/3and 5 2/5​.

firstly, convert into the improper fraction, they are, 13/3 and 27/5

now add them both  and now follow the steps,

now take out the lcm of 3 and 5 which is actually 15.

now make the denominator of both of the improper fractions equal--

(13/3)(5/5)+(27/5)(3/3)

65/15+81/15

146/15 or 9 11/15

hence ui have prooved my answer!!!

i jope you will get help from this!!!

Answer 2

Answer:

Required sum is $9 \frac{11}{15}$

Step-by-step explanation:

Given,

$4 \frac{1}{3} + 5 \frac{2}{5} \\ = \frac{4 \times 3 + 1}{3} + \frac{5 \times 5 + 2}{5} \\ = \frac{12 + 1}{3} + \frac{25 + 2}{5} \\ = \frac{13}{3} + \frac{27}{5}$

It is a problem of Fraction of Algebra.

By Fraction's addition rule,we can solve this problem.

First we are calculating LCM of 3 and 5,

LCM of 3 and 5 is 15.

So,

$\frac{13}{3} + \frac{27}{5} \\ = \frac{13 \times 5 + 27 \times 3}{15} \\ = \frac{65 + 81}{15} \\ = \frac{146}{15} \\ = 9 \frac{11}{15}$

As extra information Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about about fraction,

1.https://brainly.in/question/9833636

2.https://brainly.in/question/16383044

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