Question

find the sum of following progression2+6+10..upto 40 term​

Answer 1

Answer:

Step-by-step explanation:

the following series is in Arithmetic progression i.e., the common difference is 4 for each two terms.

so sum on n numbers in arithmetic progression is=n/2*(2*a+(n-1)*d)

n=40

d=4

a=2

sum=40/2*(4+39*4)=20*(156)=3120

Answer 2

Answer:

3200

Step-by-step explanation:

By using the formula:

Sn = n/2[ 2a + (n-1)d ] ,

Here, n= 40

a= 2

d= 4

So the answer is 3200.