Find the sum of following series, 0.9,0.91,0.92,.......100 terms
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S₁₀₀=n/2(2a+(n-1)d)
=100/2(2*0.9+(100-1)0.01)
=50(1.8+0.99)
=50*2.79
=139.5
=100/2(2*0.9+(100-1)0.01)
=50(1.8+0.99)
=50*2.79
=139.5
kvnmurty:
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