find the sum of follwing APs 2,7,12,....10terms
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2,7,12...................
common difference of given AP (d)=5 ,a =2 , n=10
Sum of n terms is an AP= n(2a+(n-1)d)/2
=10(2*2+(10-1)*5)/2
=10(4+45)/2
=5*49
= 245
2,7,12...................
common difference of given AP (d)=5 ,a =2 , n=10
Sum of n terms is an AP= n(2a+(n-1)d)/2
=10(2*2+(10-1)*5)/2
=10(4+45)/2
=5*49
= 245
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