Question

find the sum of forst 16 terms of ap 10 6 2​

Answer 1

Answer:

this is the answer ...

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Answer 2

Answer:

Given, AP is 10, 6, 2,…

Here, first term a = 10, common difference, d = -4

∴ S16 = 16/2 [2a+(16-1)d] [∵Sn = n/2{2a + (n-1)d}]

= 8 [2 × 10 + 15(-4)]

= 8 (20-60) = 8 (-40) = -320

Step-by-step explanation

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