Find the sum of Frist 10 term of an AP whose 1 term is 100 and 10 term is 1000
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3
in this question ,we have to find the common defference
solution:-
shown in attachment
hence.
the common defference of A.P is = -10 answer
## hope it helps##
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0
Answer:
5500
Step-by-step explanation:
Given:- a1=100 a10=1000
:.a=100 d=100
S = 10÷2 (2(100)+(10-1)100)
= 5(1100)
=5500
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