Question

find the sum of frist 100 natural number​

Answer 1

Step-by-step explanation:

Let S be the required sum.

Therefore, S = 1 + 2 + 3 + 4 + 5 + .................... + 100

Clearly, it is an Arithmetic Progression whose

-- first term = 1

-- last term = 100

--number of terms = 100.

[Using the formula S = n2(a + l)]

S = 100/2 (100 + 1

= 50(101)

= 5050

Therefore, the sum of first 100 natural numbers is 5050.

Answer 2

Answer:

5050

Step-by-step explanation:

Hi Anisa, hope this helps you

Sn=n÷2(2a +(n-1)d)

n=100i.e no. of terms

a=1 i. e first natural no.

d=1 i. e difference between 2 consecutive numbers

hence Sn=50(2+(99)1)

=50×101=5050