find the sum of geometric progression 1 + 3 + 9 + 27 to 12 terms
Answers
Answered by
1
Answer:1250112
Explanation:
ar^n-1
a=1
r=3
n=13
1×3^12-1=3^11
1250112
Answered by
4
Answer:
Explanation:
Formula for sum of finite terms of a GP is a(r^n-1)/r-1 [a=first term, r=common difference, n=number of terms]
Sum of the given GP is
1(3^12-1)/3-1
=531441-1/2
=531440/2
=265720
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