Physics, asked by anushree9191, 9 months ago

find the sum of geometric progression 1 + 3 + 9 + 27 to 12 terms​

Answers

Answered by Lucky567847
1

Answer:1250112

Explanation:

ar^n-1

a=1

r=3

n=13

1×3^12-1=3^11

1250112

Answered by 2singhrashi
4

Answer:

Explanation:

Formula for sum of finite terms of a GP is a(r^n-1)/r-1 [a=first term, r=common difference, n=number of terms]

Sum of the given GP is

1(3^12-1)/3-1

=531441-1/2

=531440/2

=265720

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