Find the sum of GP 1+√3+3+3√3+......to 10 terms
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Answer:
Clearly the given series is a G.P. with common ratio r=
3
and first term a=1
S
n
be the sum of first n terms of G.P.
Formula for sum of n terms of G.P. is given by
S
n
=
r−1
a(r
n
−1)
n=12 ....... (given)
Then, S
12
=
3
−1
1×((
3
)
12
−1)
⇒S
12
=
3
−1
1×((3)
6
−1)
⇒S
12
=
2
(3
6
−1)(
3
+1)
⇒S
12
=364(
3
+1)
Step-by-step explanation:
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