Question

find the sum of gp 3+6+12+....+1536
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Answer 1

Answer:

3069

Step-by-step explanation:

a=3

r=6/3=2

Tₙ=a*rⁿ⁻¹

1536=3*2ⁿ⁻¹

2ⁿ/2=512

2ⁿ=1024=2¹⁰

n=10

since r>1 then S=$\frac{a(r^n-1)}{r-1}$

S=3(2¹⁰-1)/(2-1)

=3(1024-1)/1

=3(1023)

=3069