Question

find the sum of greatest 3 digit and smallest 3 digit no. divisible by 28​

Answer 1

To find:

The sum of greatest 3 digit number and smallest 3 digit number divisible by 28.

Solution:

The numbers which are divisible by 28 are in the table of 28.

i.e.

$28 \times 1 =28\\28 \times 2 =56\\28 \times 3 =84\\28 \times 4 =112\\:\\:$

So, smallest 3 digit number which is divisible by 28 is 112.

Now, let us try to find out the largest 3 digit number divisible by 28 (which will be lesser than or equal to 999).

When we divide 999(largest 3 digit number) by 28: we get quotient as: 35

and remainder as 19.

So, if we subtract 19 from 999, we will get the largest 3 digit number which is divisible by 28.

So, largest 3 digit number divisible by 28 = 999 - 19 = 980

Now, sum of smallest 3 digit and largest 3 digit number divisible by 28  =

112 + 980 = 1092

So, the answer is 1092.