Math, asked by PragyaTbia, 1 year ago

Find the sum of
i) 1 + 4 + 7 + 10 +... to 22 terms
ii) 3 + 8 + 13 + 18 + .... + n terms


medhakrishnabehera: Java???

Answers

Answered by skqr7
0
715 this is the and for u r question
Attachments:
Answered by Suhaninahar
0

Answer:

Step-by-step explanation:

S^n= n/2 (2a+(n-1)d)

S^n=22/2( 2×1 +( 22-1)3)

Sn^= 11 (2+ 21×3)

= 11(2+63)

=11 (65)

S^n = 715

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