Find the sum of
i) 1 + 4 + 7 + 10 +... to 22 terms
ii) 3 + 8 + 13 + 18 + .... + n terms
medhakrishnabehera:
Java???
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715 this is the and for u r question
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Step-by-step explanation:
S^n= n/2 (2a+(n-1)d)
S^n=22/2( 2×1 +( 22-1)3)
Sn^= 11 (2+ 21×3)
= 11(2+63)
=11 (65)
S^n = 715
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