Question

find the sum of indicated number of terms of the following AP 0.9, 0.91, 0.92 ,........100 terms

Answer 1

sum of ap=n/2[2a+(n-1) d]
n=100
a=0.9
d=0.01
sum=50[1.8+99(0.01)]
=139.5

Answer 2

100/2 (2 (0.9)+99 (0.01))

=50 (9/5+99/100)

=139.5