Question

find the sum of integers between 100 and 200 that are divisible by 9​

Answer 1

Answer:

108,117,126.... 198 and so on

So a=108

l=198

n= ?

nth term= a + (n-1)d

198= 108+(n-1)9

198= 108+9n-9

198-99= 9n

99/9= n

n= 11

Now, sum of n terms

Sum of first 11 terms= 11/2(108+198)

=11/2(306)

=11×153

=1683

✔️Hope it will help you.✔️

Answer 2

Answer:

The answer is 1683

Step-by-step explanation:

Numbers between 100 and 200 divisible by 9 are:

108, 117, 126, 135, 144, 153,  162, 171, 180, 189, 198

Adding them up, the result is 1683.

HOPE THIS HELPS YOU..