Question

find the sum of integers between 100 and 200 that are divisible by 6​

Answer 1

Answer:

Integers between 100 and 200 divisible by6 are-

102,108,114,...198

Here a=102,d=6 last term l=198

tn =a+(n−1)d

⇒198=102+(n−1)6

⇒(n−1)6=198−102

=96

⇒(n−1)6=96⇒n−1=16

n=17

Sum= n/ 2[a+l]= 17/2[102+198]

17/2 x 300 = 150 x 17 = 2550