Question

find the sum of integers between 100 and 200 which are divisible by 7

Answer 1

Indirectly we have to find the sum of 105,112,119,126........196now lets find total no. of terms in this A.P.196=105+(n-1)*7n-1 = 91/7n=14now total sum S= 7[2*105 + (14-1)*7]S= 7[210+91]S=7*301S=2107
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Answer 2

Integers divisible by 7 between 100 and 200 are : 105,112,....,196
This forms an ap
with a=105 , d=7 , l=196
Since l=196
a+(n-1)d=196
105+(n-1)7 = 196
(n-1)7 = 91
n-1=13
n=14
So sn =n/2(a+l)
=14/2(105+196)
=7×301
=2107
Hope it will help u