find the sum of integers between 100 and 500 that are multiple of 11.
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0
Answer:
110 ,121,132,143,154165,176,187,198,
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2
Answer:
the mutiples of 11 in between 100 and 500 are 110,121,132,...............495.
a=110, d=11
let 495 be nth term of the AP.
an=a+(n-1)d
495=110+(n-1)11
495-110=(n-1)11
385=(n-1)11
n-1=385/11
n=35+1
n=36
S36=[n/2[a+l]
=36/2[110+495]
=18×605
=10890
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