find the sum of integers between 140 and 250 that are divisible by 6 fully explained
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Step-by-step explanation:
Ans = 390
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Answered by
0
Step-by-step explanation:
a=144 (as it's the 1st term after 140 that is divisible by 6)
an=246(as it's the last term b4 250 that is divisible by 6)
d= 6
an=a+(n-1)d
246=144+6n-6
246-144+6=6n
108=6n
n=108/6
n= 18
sn=n/2{2a +(n-1)d}
s18= 18/2 {2×144+(18-1)6}
s18=9{288+102}
=9(390)
=3510
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