Find the sum of integers from 11to1000 which are divisible by 3
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Integer that are divisible by 3from 11to 1000 are
12,15,18.............................999
Now, Sum =12+15+18....................+999
=3(4+5+6...............+333)
We know that, sum of first n integers n(n+1)/2
It can also be written as
S=3[(1+2+3+4+5+6............+333) -(1+2+3)]
=3[{333(334)}-(6)]
=3*[55605]
=166815
This is your answer.
Plzz mark as brainlist.
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