Question

Find the sum of integers which are divisible by 5 from 6 to 150​

Answer 1

Solution:-

Let,

x = (5+10+15+20+25+...+145+150)-5

x = 5(1+2+3+4+5+...+29+30)-5

Here, n = 30

WKT

Sum of Integers = n(n+1)/2

$→\;\Large{\sf{\frac{5×30(30+1)}{2}-5}}$

$→\;\Large{\sf{\frac{5×30×31}{2}-5}}$

$→\;\Large{\sf{\frac{4650}{2}-5}}$

$→\;\Large{\sf{2325-5}}$

$☞\;\Large{\bf{2320}}$

• Therefore, Sum of integers required is 2320.

$\Large{✓}$

Hope It Helps You ✌️