Question

Find the sum of integers which are divisible by 5form 1to 100

Answer 1

Answer:

Step-by-step explanation:

It forms an AP

5,10,15.......100

First term (a) =5

Common difference (d) = 5

Last term, l = 100

ntn term =100

a +(n-1)d = 100

5 +(n-1)5 = 100

(n-1)5= 95

n-1 =19

n = 20

Sn=n/2(a+l)

=20/2(5+100)

=10*105

=1050

Thus sum is 1050

Hope it helps...