Question

find the sum of interior angle of a polygon with 10 side​

Answer 1

Step-by-step explanation:

No. of sides = 10

sum of interior angles = 180⁰ X (no of sides -2)

= 180⁰ × (10-2)

= 180⁰ X 8 = 1440⁰

Answer 2

Answer:

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find the sum of interior angle of a polygon with 10 side

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A polygon with 10 side

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Sum of Interior Angles = (no. of sides−2) × 180°

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$let \: n = 10 \\ ⟹(n - 2) \times 180° \\⟹ (10 - 2) \times 180° \\⟹ 8 \times 180 \\⟹ 1440°$

${\boxed {\boxed {sum\:of\: interior\:angle=1440°}}}$

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