Question

Find the sum of interior angles of a polygon which has i) 30 sides, ii) 40 sides. ​

Answer 1

Answer:

1.5040

2.6840

Step-by-step explanation:

1. n=30

so,(n-2)180

(30-2)180

(28)180

5040

2. n=40

(40-2)180

(38)180

6840

Answer 2

Step-by-step explanation:

Question:-

Find the sum of the interior angle of a polygon which has 30 sides and 40 sides

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Given that:-

Sides of the first polygon = 30 sides

Sides of the second polygon = 40 sides

To find:-

The sum of interior angles.

Answer:-

Sum of interior angles of a polygon=

30 sides is 5040°

40 sides is 6840

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\bold{STEP-BY-STEP-EXPLANATION}STEP−BY−STEP−EXPLANATION

Sum of measure of all interior angles = ( n-2 ) × 180°

( i ) 30 sides:-

\implies⟹ \tt{(30-2)×180}(30−2)×180

\implies⟹ \tt{28×180}28×180

= 5040°

( ii ) 40 sides:-

\implies⟹ \tt{(40-2)×180°}(40−2)×180°

\implies⟹ \tt{38×180}38×180

= 6840°

Therefore , the sum of the interior angle of a polygon which has 30 sides 40 sides is 5040° and 6840°

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