find the sum of interior angles of a rectangular polygon of sides n
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exterior angle = 360/n
interior angle = 180- (exterior angle)
= 180 -(360/n)
sum of n angles = n*{180- (360/n)}
= n* 180{ 1 - (2/n)}
=n*180{n-2}/n
= (n-2)*180
interior angle = 180- (exterior angle)
= 180 -(360/n)
sum of n angles = n*{180- (360/n)}
= n* 180{ 1 - (2/n)}
=n*180{n-2}/n
= (n-2)*180
nilanjanryon21p60n0p:
ab samjha
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18o hi hoga sum of interior angles
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