find the sum of interior angles of hexagon by dividing it into triangles
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Given Find the sum of interior angle of hexagon ABCDEF by dividing it into triangles.
We need to find the sum of interior angle of given hexagon.
In the figure if we join BD,BE and BF we get four triangles. They are BDC, EBD, FBE and ABF.
We have sum of all the angles of a triangle = 180 degree
Therefore sum of angles in four triangles will be 180 x 4 = 720 degree
So the sum of all the angles in a hexagon is 720 degree
Therefore sum of all interior angles of hexagon ABCDEF will be 720 degree
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