Question

Find the sum of largest and lowest value of the solution set of the inequality [3x- 2]<= 1/2​

Answer 1

|3x-2| ≤ 1/2

Opening the mode With +ve Sign:

3x-2 ≤ 1/2

x ≤ 5/6------a

Opening mode with -ve Sign:

-3x+2 ≤ 1/2

1/2≤x------b

therefore, From a & b We get the limit value of x:

$\sf \: \frac{1}{2} \: and \: \frac{5}{6}$

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