Find the sum of last 21 terms of the AP:-
8,10,12..............126.
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1
Answer:
I
Step-by-step explanation
If we have to find the sum of last 21 terms of an ap then we have to take
a= 126 d= -2
Now applying the formula
S = n/2 (2a +(n - 1)d )
Putting the values..
S= 21/2 (2×126 + (21 - 1)-2)
= 21/2 (252 + 20 × (-2) )
= 21/2 (252 - 40)
= 21/2 (212)
=21× 106
=2226
superiortanu12378:
Thanks for thanks
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