Question

Find the sum of last ten terms of the A.P.
8, 10, 12, ......, 126.​

Answer 1

Answer:

an=a+(n-1)d

126=8+(n-1)2

118/2=n-1

59+1=n

60=n

sn=n/2(a+l)

=60/2(8+126)

=30(134)

=4020

Mark me as brainliest

Answer 2

Step-by-step explanation:

ₐ/c ₜₒ qᵤₑₛₜᵢₒₙ ,

wₑ ᵢₙᵥₑᵣₜ ₜₕᵢₛ ₛₑᵣᵢₑₛ ,

₁₂₆ , ₁₂₄ , ₁₂₂ ,........₈

ₙₒw,

fᵢᵣₛₜ ₜₑᵣₘ ₒf ₙₑw ₐₚ ᵢₛ ₌ ₁₂₆

cₒₘₘₒₙ dᵢffₑᵣₑₙcₑ ₌ ₋₂

ᵤₛₑ fₒᵣₘᵤₗₐ,

ₛₙ ₌ₙ/₂ {₂ₐ ₊₍ₙ₋₁₎d

ₛ₁₀₌₁₀/₂{₂ × ₁₂₆ ₊₍₁₀₋₁₎₍₋₂₎}

₌₅{₂₅₂ ₋₁₈}

₌₅ × ₂₃₄

₌₁₁₇₀

ᵃ/ᶜ ᵗᵒ qᵘᵉˢᵗⁱᵒⁿ ,

ʷᵉ ⁱⁿᵛᵉʳᵗ ᵗʰⁱˢ ˢᵉʳⁱᵉˢ ,

¹²⁶ , ¹²⁴ , ¹²² ,........⁸