find the sum of lengths of parallel sides of trapezium whose altitude is 11 cm and whose area is 0.55 m square
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Answered by
10
a=1\2×(a+b)×h
a+b=10 meter
a+b=10 meter
Answered by
8
0.55= 1/2×(x+x)×11
0.55= (x+x) ×5.5
2x×5.5 =0.55
x =0.55÷11
x=0.5
0.55= (x+x) ×5.5
2x×5.5 =0.55
x =0.55÷11
x=0.5
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