Find the sum of m terms of an A. P. whose nth terms is given by an= 5 − 6n.
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a1 = 5-6n
= 5-6(1)
= - 1
a2 = 5- 6 ( 2 )
= - 7
d = -7 + 1
= -6
Sm = n/ 2 [ 2 a + ( m - 1 ) d ]
Sm = m / 2 [ -2 + ( m - 1 ) -6 ]
Sm = m / 2 ( - 2 - 6 m + 6 )
Sm = m / 2 ( -6m +4 )
Sm = m / 2 ( -3m + 2 ) 2
sm = -3 m square + 2 m
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