find the sum of m terms of an AP. whose nth terms is given by an=5-6n
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first term = a1 = 5-6n=5-6(1)=5-6= -1
2nd term = a2= 5-6n=5-6(2)=5-12= -7
common difference = d = a2-a1
-7-(-1)= -7+1= -6
nth term = a + (n-1)d
-1+(n-1)-6= -1 -6n+6= -6n+5
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