find the sum of measure of interior angles of a polygon having number os sides 5.
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(n-2)×180
(5-2)×180
3×180
540° is answer
(5-2)×180
3×180
540° is answer
vishnu200646:
yes you are right
Answered by
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no of sides=n=5
sum of angles = (n-2)×180
=(5-2)×180
=3×180=540°
Hence, sum of measure of interior angles of a polygon having number of sides 5 is 540°.
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